0.4-0.1x^2=0

Solution for 0.4-0.1x^2=0 equation:

0.4-0.1x^2=0

a = -0.1; b = 0; c = +0.4;
Δ = b2-4ac
Δ = 02-4·(-0.1)·0.4
Δ = 0.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.16}}{2*-0.1}=\frac{0-\sqrt{0.16}}{-0.2}
=-\frac{\sqrt{}}{-0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.16}}{2*-0.1}=\frac{0+\sqrt{0.16}}{-0.2}
=\frac{\sqrt{}}{-0.2}
$